09-05-2019, 06:44 PM
The acceleration a is considered to be constant at 1 ft/s^2. To get velocity v we integrate a with respect to time t.
v = INTEGRAL a dt = at + v0 where v0 = initial velocity.
To get position x we integate v with respect to t.
x = INTEGRAL (at + v0)dt = 0.5at^2 +v0t + x0 where x0 = initial position.
t = 0 v = 0 x = 0
t = 1 v = 1 x = 0.5
t = 2 v = 3 x = 2.5
t = 3 v = 6 x = 7
t = 4 v = 10 x = 15
t = 5 v = 15 x = 27.5
t = 6 v = 21 x = 45.5
t = 7 v = 28 x = 70
t = 8 v = 36 x = 102
t = 9 v = 45 x = 142.5
t = 10 v = 55 x = 192.5
v = INTEGRAL a dt = at + v0 where v0 = initial velocity.
To get position x we integate v with respect to t.
x = INTEGRAL (at + v0)dt = 0.5at^2 +v0t + x0 where x0 = initial position.
t = 0 v = 0 x = 0
t = 1 v = 1 x = 0.5
t = 2 v = 3 x = 2.5
t = 3 v = 6 x = 7
t = 4 v = 10 x = 15
t = 5 v = 15 x = 27.5
t = 6 v = 21 x = 45.5
t = 7 v = 28 x = 70
t = 8 v = 36 x = 102
t = 9 v = 45 x = 142.5
t = 10 v = 55 x = 192.5
![[Image: 4CV0TeR.png]](https://i.imgur.com/4CV0TeR.png)